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What Is The Equation For The Graph Of Y X 2 If The Vertex Is 1 17 And The Parabola Is Congruent In Shape To The Graph Of Y 3x 2 Quora

y = a(x – h) 2 k, where (h, k) The axis of symmetry of a parabola is a vertical line that divides the parabola into two congruent halves The axis of symmetry always passes through the vertex of the parabola The x coordinate of the vertex is the equation of the axis of symmetry of the parabolaAbout Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How works Test new features Press Copyright Contact us Creators

Parabola congruent to y=x^2

Parabola congruent to y=x^2-A parabola is congruent to y=x^2 and has xintercepts 1 and 5 determine the coordinates of the vertex Answer by Fombitz() ( Show Source ) You can put this solution on YOUR website!Algebra questions and answers 11 Write an equation for a parabola with a) Maximum at 2 and equation of the axis of symmetry x=2 congruent to y=x b) Congruent to y = 8x, minimum at (2,8) Question 11 Write an equation for a parabola with a) Maximum at 2 and equation of the axis of symmetry x=2 congruent to y=x

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If we put x = 0 we obtain y = 9 and this is called the yintercept The graph of y = (x − 3)2 is congruent to the basic parabola, but is translated 3 units to the right We can confirm this with a table of values Similarly, the graph of y = (x 5)2 is congruent to the basic parabola, but is translated 5 units to the leftTest a point that is not on the boundary?11 The graph below shows two congruent triangles, ABC and A'B'C' Which rigid motion would map ABC onto A'B'C'?

The axis of symmetry of a parabola is a vertical line that divides the parabola into two congruent halves The axis of symmetry always passes through the vertex of the parabola The x coordinate of the vertex is the equation of the axis of symmetry of the parabola For a quadratic function in standard form, y = a x 2 b x c , the axis ofThe set of points (x, y) whose distance from the line y = 2 x 2 is the same as the distance from (2, 0) is a parabola This parabola is congruent to the parabola in standard form y = K x 2 for some K which is equal to Explanation the equation of a parabola in vertex form is ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯∣∣ ∣ 2 2y = a(x − h)2 k2 2 ∣∣ ∣ −−−−−−−−−−−−−−−−−−−−− where (h,k) are the coordinates of the vertex and a is a multiplier here (h,k) = (2, −4) ⇒ y = a(x − 2)2 −4 to find a substitute (1, − 1) into the equation −1 = a − 4 ⇒

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Shade inside the parabola? Parabola described by y=2x^2 is narrower than the parabola described by y=x^2 Parabola described by y=2x^2 is narrower than the parabola described by y=x^2 Smaller the coefficient of x^2 wider the curve

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